#Exercise 1 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string[-1])


#Exercise 2 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string[7])


#Exercise 3 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string[-10])


#Exercise 4 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string.index("B"))


#Exercise 5 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string.count("o"))


#Exercise 6 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string.upper())


#Exercise 7 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string.find("Bitcoin"))


#Exercise 8 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string.startswith("X"))


#Exercise 9 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string.swapcase())


#Exercise 10 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string.replace(" ", ""))


#Exercise 11 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string.replace("i", "btc"))


#Exercise 12 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string.split(","))


#Exercise 13 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print("&".join(my_string))


#Exercise 14 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."
my_other_string = "Poor guy!"

print(my_string + my_other_string)


#Exercise 15 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string.title())


#Exercise 16 - Solution
my_string = "In %s, someone paid %s %s for two pizzas."

print(my_string % ("2010", "10k", "Bitcoin"))


#Exercise 17 - Solution
my_string = "In {}, someone paid {} {} for two pizzas."

print(my_string.format("2010", "10k", "Bitcoin"))


#Exercise 18 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string[3:7])


#Exercise 19 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string[-23:-16])


#Exercise 20 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string[:12])


#Exercise 21 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string[-9:])


#Exercise 22 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string[::-1])


#Exercise 23 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string[::7])


#Exercise 24 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string[10:])


#Exercise 25 - Solution
my_string = "In 2010, someone paid 10k Bitcoin for two pizzas."

print(my_string[:-4])